Question

Solve system of equations
2x+y+3=0
x^2+y^2=5

Answer 1

i think I'm going retarded looking at math problems @Tranquility @Hero

Answer 2

For the first equation, isolate y, then substitute the expression for y in the second equation.

Answer 3

5x^2+12x+9=5 ?

Answer 4

How would you continue

Answer 5

You now have a quadratic equation that you can solve for \(x\).

Answer 6

Yes. I know.
How would you do that?

Answer 7

Start by simply subtracting 5 from both sides. Once you do that you'll have a quadratic equation in the form \(ax^2 + bx + c = 0\) where a, b, and c are coefficients. You can use the quadratic formula to solve for \(x\). Using the quadratic formula will result in two values of \(x\) which is appropriate here since the line and the circle intersect at two points.

Answer 8

Thank you :)

Answer 9

Don't forget to find the \(y\) values as well.

Answer 10

So then you would plug the x variable in one of the formulas to find y?

Answer 11

Your answer should be in a form such as \((x_1,y_1)\) and \((x_2, y_2)\) are the points that represent the solution to the system.

Answer 12

Once you find the \(x\) values, plug them in to the linear equation to find the \(y\) values.

Answer 13

thank u !!!

Answer 14

YW