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@Narad
Using CPCTC, we can conclude that D≅A. We can then conclude that (5y-10)°=45°. You can solve from here.
so find y?
@Narad
That's the answer
whats the answer
\[5y-10=45\]
but I have to find y?
Yes, you must solve this equation
\[\Delta ABC = \Delta DFE\] \[AB=DF\] \[2x-4=10\] Solve this equation to find x?
nº3 \[\Delta RSV= \Delta TVS\] \[RV=ST\] \[\frac{ 1 }{ 2}x-1=5\]4 Solve for x?
4 has nothing to do
nº4 \[\Delta ABC= \Delta DEF\] angle E = angle B \[x+10º=65º\] Solve this equation for x?
nº5 \[\Delta ABC= \Delta DEF\] \[ED= AB\] \[3x-4=x+8\] Solve this equation for x?
nº6 \[\Delta WSR = \Delta TVR\] \[\frac{ WR }{ WS}= \frac{ TR }{ TV }\] \[\frac{ x+2 }{ 10 }=\frac{ x+6 }{ 20 }\] Solve for x?
nº7 \[\Delta QVS= \Delta RTS\] \[\frac{ QV }{ RT }=\frac{ VS }{ TS }\] \[\frac{ x }{ 14}=\frac{ 8 }{ 4 }\] Solve this equation for x?
nº8 \[\Delta QPT =\Delta QRS\] \[\frac{ QS }{ QT}=\frac{ RS }{ PT}\] \[\frac{ x }{ 20 }=\frac{ 8 }{ 12}\] Solve this equation for x?
nº9 \[\Delta JKL= \Delta MPL\] \[\frac{ JK }{ PM }= \frac{ KL }{ PL }\] \[\frac{ x }{ 22} = \frac{ 10 }{ 16 }\] Solve this equation for x?
nº10 \[\Delta MOP= \Delta MNQ\] \[\frac{ OP }{ NQ } = \frac{ MO }{ MN }\] \[\frac{ x }{ 5 } = \frac{ (15+3) }{ 15 }\] Solve this equation for x?
\[\Delta ABC = \Delta DEF\] angle F= angle C \[2x-8=50\] Solve this equation to find x?
Yes \[\Delta ABC= \Delta DEF\] \[DF=AC\] \[\frac{ 1 }{ 2 }x-1=10\] Solve this equation for x?
\[\Delta RSV = \Delta TVS\] \[VT=SR\] \[2x+8=24\] Solve this equation for x?
\[\Delta ABC = \Delta DFE\] \[FE= BC\] \[3x-4=20\] Solve this equation to find x?
\[\Delta ABC= \Delta DFE\] angle D = angle A \[2y+20=45\] Solve this equation for y?
\[\Delta JKL = \Delta PML\] \[\frac{ JK }{ JL }=\frac{ PM }{ PL}\] \[\frac{ x }{ 2 }=\frac{ 20 }{ 10 }\] Solve this equation for x?
\[\Delta QPT = \Delta QRS\] \[\frac{ QS }{ RS }=\frac{ QT }{ PT}\] \[\frac{ x }{ 20 }=\frac{ 40 }{ 24}\] Solve this equation for x?
\[\Delta QVS= \Delta RTS\] \[\frac{ VS }{ VT }= \frac{ QV }{ RT }\] \[\frac{ x }{ 8}=\frac{ 10 }{ 6 }\] Solve this equation for x?
\[\Delta ABE = \Delta ACD\] \[\frac{ BE }{ CD }=\frac{ AB }{ AC}\] \[\frac{ x }{ 5 }= \frac{ 4 }{ 10}\] and \[\frac{ BE }{ CD }=\frac{ AE }{ AD }\] \[\frac{ x }{ 5} =\frac{ y }{ (y+2) }\] Therefore, \[\frac{ y }{ (y+2) }=\frac{ 4 }{ 10 }\] Solve this equation for y?
\[\Delta QVS = \Delta RTS\] \[\frac{ VS }{ TS} = \frac{ QV}{ RT }\] \[\frac{ x }{ 12 }=\frac{ 5 }{ 3 }\] Solve this equation for x?
okay thank you
You are welcome
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