Which equation is y=-3x^2-12x-2 rewritten in vertex form
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Hello! Welcome to QuestionCove! This is the vertex form y = a(x - h)^2+ k where (h, k) is the vertex To find the x-coordinate of the vertex it's -b/2a when the equation is in the form ax^2 + bx + c You can then plug in the x-coordinate of the vertex into the equation to find the y-coordinate of the vertex. You then plug in those two values into the vertex form of the equation
Good start, but find the vertex to plug into the vertex form does not guarantee that a=1. This is why you must apply complete the square to convert standard form to vertex form: \[-3x^2-12x-2\] \[-3(x^2+4x+c)=2+(-3c)\] Apply what you know about perfect square trinomials and c=4 since (b/2)^2 = 2^2. \[-3(x^2 + 4x + 4)=2-12\] \[-3(x+2)^2 = -10\] \[y=-3(x+2)^2 +10\]
Good point, completely slipped my mind. Thank you for the correction
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