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@Vocaloid
You must be familiar with the properties of all regular and basic polygons. The diagonals for an isosceles trapezoid are always congruent. Option B.
@Vocaloid
3. You must know the properties of all polygons. At least sketch a kite. Diagonals don't bisect. 4. This conditional statement is true.
@Ferredoxin4
Property of parallelograms: Parallel sides of a parallelogram are always congruent. AB is parallel to CD and BC is parallel to AD. This leads you to the conclusion that AB=CD and BC=AD. We can now formulate the respective equations. (1)...2x-y=7 for AB=CD (2)...x+y=2 for BC=AD I'd now use elimination between the two systems, find x, then plug and chug and find y.
can I just put 2x-y=7 equal to x+y=2 ?
First you can't really make two systems 'equal' to each other, you can only isolate one variable and then find the other. Second by making them equal, you are implying that AB=AD or CD=BC, which is not necessarily true in all parallelograms.
I'd suggest using elimination between the two systems and eliminate the y since their coefficients are already opposite values. Then add the x terms and the constants on the other side, find x using division property of equality. Once you have x, I'd substitute that x value in the second equation (or first, whatever is your preference, but I chose second because less math) and find y using subtractive property of equality. You'll get your x and y values then.
Can you help me through it please, because its quite confusing
Do you understand the logic I used for the parallelogram?
Given that ABCD is a parallelogram, we can use the property that non-intersection, parallel sides must always be congruent. This is true as long as the polygon is a parallelogram. What are the parallel sides here?
bc and ad?
correct, what's the other pair?
cd and ba?
correct. So using the property I gave you, what do you think is true of these pairs?
The parallel segments would be...
congruent
correct, so thereby you can imply that the values given are equivalent. You can say that AB=CD and BC=AD do you get that?
Yes
So you can use the values given: AB=2x-y CD=7 and you know that AB=CD So then you can say that 2x-y=7 correct?
Yes okay
Apply the same logic with the other pair. BC=AD we know that BC=x+y and AD=2 so x+y=2
You now have two equations for each pair, AB=CD is 2x-y=7 BC=AD is x+y=2 So now you have a system of linear equations. Do you know how to do those?
Im not sure
Elimination, substitution, Cramer's rule, etc...you know these terms?
Okay, not Cramer's rule, but do you recall elimination and substitution from Algebra 1?
Yes I do
Do you know how to do those, specifically elimination in this case?
I forgot about the elimination method
Okay so here's what you would do: Your equations are \[(1)...2x-y=7\] \[(2)...x+y=2\] You can add these two without having to change the equations one of the like-variable's coefficients are opposite values of each other (-y and y) 2x-y=7 x+y=2 Add these 2 equations 3x=9 x=3 We have our x value as 3. Now plug and chug in one of the equations and find y. x+y=2 (3)+y=2 y=2-3 y=-1 so x=3 and y=-1. We can ensure these values are correct using inductive reasoning.
So thats the x and y ? so those are the answers?
yes, x=3 and y=-1
AC = 2x+9 BC = 8x-3 2x+9=8x-3 find x??
x=2
like that?
yes, but do you know why we did AC=BC?
Point C is on the perpendicular bisector of AB.
No, there is not enough information to conclude that point C, which lies on segment AC, is a perpendicular bisector of AB.
The reason why we can do AC=BD is because a property of isosceles trapezoids is that their diagonals are equivalent.
AE = EC 1/2b + 1 = b - 15
Correct, now do you know why you equate AE to EC?
b = 32
they were both given
AE = EC the same as BE = ED
yes b is 32 but why?
No, it's because another property of parallelograms: Diagonals intersect at their midpoints.
yes thats another reason
then to find AE we have to substitute the b
AE = 1/2(32) + 1
AE = 16+1
which is 17
so AE is 17.
Correct?
@Ferredoxin4
I was away, I'm back. Let me see.
correct.
34=2x-10 x=22 ?
yes correct
Measure of L is the same as M. Since M equals 66, then L also is 66.
correct
y=-x+4, SV=VS, 1=4x-y
y=-x+4 into 1=4x-y 1=4x-(-x+4) => 1=4x+x-4 => 1=5x-4 => 1+4=5x-4+4 => 5=5x => 5/5=5x/5 => x=1
Correct, due to CPCTC. Now use systems of linear equations (I would use substitution)
x=1 into y=-x+4 y=-x+4=-1+4=3
x=1, y=3 ?
Correct x=1 and y=3
We can draw several implications here and eventually conclude that 2x+3=40, then solve for x.
x=37/2
yes
Using CPCTC we can conclude that BC=EF. This means that 3x-5=x find x
x=5/2
correct
Incorrect. Don't make implications off of the graphic, as it may trick you. It says that ABC=DFE. Using CPCTC, we can say that angle F is equal to angle B, or that 3x-1=100. Now solve for x.
okay 101/3
yes
I'd say mark up the diagram so it's easier to understand, or draw it on paper.
wouldnt it just be 4 and 6
AB of the shorter triangle and AC of the larger triangle are similar segments. Similar segments are a proportion. This means we can say that \[\frac{ AB }{ AC } = \frac{ BE }{ CD }\] Plug in their values AB=4 AC=6 BE=x CD=3
\[\frac{ 4 }{ 6 }=\frac{ x }{ 3 }\] x would be 2.
Ohh okay that makes sense
16/8 = x/20
x=40
Correct.
Use proportions We can say that TV~WS and WR~TR Then make the proportion: \[\frac{ 18 }{ 10 } = \frac{ x+6 }{ x+2 }\] Use cross multiplication and find x
x=3
yes
same concept as before, form a proportion on the similar segments
12/8=x+14/x+8 ?
yes correct
x=4
yes
5x-6=2x+12?
correct, do you know why?
because thats the measure of the two triangles
no, it doesn't have to do with triangles. Since both angles x and y share the same arc, which is arc WZ, we can conclude that angles x and y are congruent.
oh okay
@Ferredoxin4
Use the distance formula:
This one doesn't need it though, just imagine the points on the cartesian plane or draw a sketch. It would be 1 unit away.
So first you can graph the function using a few test points. Do you know how to calculate focus and directrix?
No im not sure
okay here's how you would do it: 1. First change the equation so it matches this: 4py=x^2, where 4p=a 2. Find p. 3. if a>0, then the focus is k+p and the directrix is y=k-p, where k is from (h,k) Graph them
Correction to #1, you would convert it to (x-h)^2 = 4p(y-k) if it's a vertical axis I just wrote that because in this case there is no bx or c value.
4p=a remains the same.
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