Question

What is ΔE for the transition of an electron from n = 8 to n = 4 in a hydrogen atom? What is the frequency, ν, of the spectral line produced?

Enter your answers with 4 significant digits.

Express your answer for ΔE in J
Express your answer for ν in s−1.

Answer 1

@dude

Answer 2

@Tranquility

Answer 3

I got:
∆E = 1.020 x 10^-19 J
v = 1.539 x 10^14 s^-1

But it was wrong. Can you help?

Answer 4

∆E = (-13.6/8^2 - (-13.6/4^2) ) x 1.6x10^-19 = 1.02 x 10^-19 J
I used the Bohr model for energy to find delta ∆E and used 1.6x10^-19 to convert to Joules.
v = ∆E/h = 1.02 x 10^-19/6.626x10^-34 = 1.5393 x 10^14 s^-1

Answer 5

@Vocaloid

Answer 6

My v value is correct, but it says my ∆E value isn't. I think it has to do with something with the four significant digits

Answer 7

((-13.6/(8^2) - (-13.6/4^2))) * 1.6022*10^-19 = \(\boxed{1.021\times 10^{-19}}\)

1 eV = 1.6022*10-19 J
maybe using 1.6022 instead of 1.6

Answer 8

I ended up figuring it out, it was that it was -1.021 since energy was lost. but thanks!

Answer 9

Glad you figured it out!

It's interesting that the - sign is required since we're calculating the change (\(\Delta\)) in energy