Math help.
|dw:1567820791452:dw|
|dw:1567820837096:dw|
|dw:1567821200406:dw|
There you go. Correct.
Yuss!
The next one is a bit hard, plz check my work
|dw:1567821265860:dw|
|dw:1567821425952:dw|
Is this it?
Yes it's correct but just note that you did g(f(x), not f(g(x))
Sorry, i meant g(f(x)) . Hold on i have a question for u
What if i want to flip the denominator ?? Will the signs in the denominator change? Let me draw for u
|dw:1567821956120:dw|
No when you move things up and down the numerator/denominator, You are not changing the sign of the function. Instead, you are changing the sign of the exponent.
For instance 1/x = x^ -1
Yeah thats what i was thinking
So instead, you are keeping the sign of the term constant, but you are raising the full term to the -1 power. (x^3 + 1 -x) ^-1
But my textbook, has the answer as f(g(x)) = x^3 +1 -x....
Let me check one more time
|dw:1567822217082:dw|
Ah, I forgot to realize you're using the same functions. The numerator is x, not 1.
yeah
let me point out your error
The error you made is when you muliplied 1/x again, when x should've been the common denominator.
x was the common denominator, there's no reason to multiply 1/x with x again. Just do multiply it to x^2 and 1.
Okie
Is this from algebra 2?
This is from my college calc fundamentals prerequisites section...
So did we find why’s there an x in the numerator?
Because the denominator has a fraction itself 1/((x^3+1-x)/x) the reciprocal of that brings the x up.
Ah, so are you taking calc 1 and 2 after?
I don’t wanna think about it... i get depressed....i don’t wanna think and lose motivation ...
Let me draw the thing...hol up
Uhgg they sneaky Wizards..... i see what they did..but i didnt take the LCD but instead made the fractions equivalent...let me do it but taking the lcd
|dw:1567824147571:dw|
No you did it a bit wrong. What is the LCD of x and x^2?
There’s a 1 in the denominator of x^2
It should be x because that is the LCM
Can you show me? Plz
You multiply x^2 with x and -1 with x. right?
That's all you need to do. And then simplify.
That’s what i was doing tho
So it then becomes 1/((x^2(x) +1 -1(x))/x)
And you get 1/((x^3+1-x)/x)
|dw:1567824687738:dw|
So you just simplify from there..
How do u take the lcd of a variable ???
Just like how you would do with numbers For instance 8 and 4 8 -> 4 and 2 4 -> 4 works similarly x^2 and x x^2 -> x and x x -> x.
X goes into x once..
Yeah so you would continue from there
|dw:1567824852060:dw|
Right. So simplify the x(x)^2 + 1 -x
You get x^3 + 1 -x
So you have |dw:1567824950784:dw|
|dw:1567824931428:dw|
Yes there you go
Jesus..
Thanks bro...really appreciated
I suggest that you watch the topics being explained online (youtube) instead of simply from the book.
I will
Thanks
This book is literally written by our prof lol
oh boy
Yeah let’s not scare me lol
K i’ll Catch you on the next one. Thanks
np
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