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Mathematics 16 Online
Ballery1:

Math

Ballery1:

Express the given relation in logarithmic form \[3^4 = 81\]

Ferredoxin4:

I always use this mnemonic: exponential form BEN Base ^ exponent = number Logarithmic form BNE log BASE number = exponent

Ferredoxin4:

So now try? What is the base, exponent, and number?

Ballery1:

3

Ferredoxin4:

base is 3, exponent is 4, and number is 81. It is given in BEN form Change it to BNE

Ballery1:

|dw:1568167203427:dw|

Ballery1:

What’s bne

Ferredoxin4:

BNE = Base - number - exponent. Give a moment, I'll explain.

Ballery1:

And ben

Ballery1:

Actually i know that stuff i just wanna know how do u transition from ben to bne

Ballery1:

To log form

Ferredoxin4:

Exponent form \[base^{exponent} = number\] Logarithmic form \[\log_{base}number = exponent\]

Ferredoxin4:

So you don't need much math, you're legit just moving stuff around

Ballery1:

I need you to write that method for me... I need to see every single step ...i’ll Use that as a template to do the rest of the questions

Ferredoxin4:

Oh dear That's the template, there's no steps for it. I'll give a few examples 3^5 = 243 so in log form \[\log_{3}243=5\]

Ballery1:

I can write an exponent expression in log form. I need the steps

Ferredoxin4:

Math isn't like a cookbook, some things are implied, while others are derived. I think I gave a pretty good tip here, but if it doesn't do enough then maybe @mhchen can help out

mhchen:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Ballery1 Express the given relation in logarithmic form \[3^4 = 81\] \(\color{#0cbb34}{\text{End of Quote}}\) \[\log_{3}{(3^4)} = \log_{3}(81)\]

mhchen:

And there's this formula: \[\log_{a}{a^{b}} = b\]

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