Math
Express the given relation in logarithmic form \[3^4 = 81\]
I always use this mnemonic: exponential form BEN Base ^ exponent = number Logarithmic form BNE log BASE number = exponent
So now try? What is the base, exponent, and number?
3
base is 3, exponent is 4, and number is 81. It is given in BEN form Change it to BNE
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What’s bne
BNE = Base - number - exponent. Give a moment, I'll explain.
And ben
Actually i know that stuff i just wanna know how do u transition from ben to bne
To log form
Exponent form \[base^{exponent} = number\] Logarithmic form \[\log_{base}number = exponent\]
So you don't need much math, you're legit just moving stuff around
I need you to write that method for me... I need to see every single step ...i’ll Use that as a template to do the rest of the questions
Oh dear That's the template, there's no steps for it. I'll give a few examples 3^5 = 243 so in log form \[\log_{3}243=5\]
I can write an exponent expression in log form. I need the steps
Math isn't like a cookbook, some things are implied, while others are derived. I think I gave a pretty good tip here, but if it doesn't do enough then maybe @mhchen can help out
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Ballery1 Express the given relation in logarithmic form \[3^4 = 81\] \(\color{#0cbb34}{\text{End of Quote}}\) \[\log_{3}{(3^4)} = \log_{3}(81)\]
And there's this formula: \[\log_{a}{a^{b}} = b\]
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