Question

math help plz :)

Answer 1

\[f(x) = e ^{9x^2-1}\]

Answer 2

i have two questions.
first, how do i plugin e^-1 when i set the function to f(0)?
second, will i get the right answer for f(0) if i plugin 2.7182818284^-1?

Answer 3

1. f(0) would end up yielding e^-1. Use your knowledge of exponents. That would be 1/e, correct?

2. Of course. But just take it's reciprocal instead, or however you want to do it.

Answer 4

yes i know the reciprocal is y = 1/e and yupp, i'm getting the same thing 0.367879441...so the function is continuous

Answer 5

i don't see any value of x that'd make the function discontinued at any way

Answer 6

In order to tell if a function is continuous at a point the function must satisfy these points:
f(c) is defined
limx->a+ = limx->a -
limx->a = f(c)

Answer 7

Yeah it's continuous and also differentiable.

Answer 8

k thanks bro :)

Answer 9

calc

Answer 10

let me finish this first plz :)

Answer 11

i do have more and freaky questions tho