Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean mu and standard deviation sigma. Also, use the range rule of thumb to find the minimum usual value mu minus 2 sigma and the maximum usual value mu plus 2 sigma.

n=1580,=1/4

Question

Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean mu and standard deviation sigma. Also, use the range rule of thumb to find the minimum usual value mu minus 2 sigma and the maximum usual value mu plus 2 sigma.

n=1580,=1/4

JSVSL7 · Answer

Use expected value to calculate for the mean.

For binomial distributions $B(n,p,k)$, mean or expected value is $np$
The standard deviation or Sx is $√(np(1-p)$

JSVSL7 · Answer

For a moment I forgot range rule of thumb, I think it was that the range is always 4 times the standard deviation of the population/sample

JSVSL7 · Answer

But once you get your expected value and Sqx, you can find the minimum usual and maximum usual values.