Question

Math help plz

Answer 1

I need to simplify this equation to find the inflection point...

Answer 2

nah...

Answer 3

Aww...

Answer 4

first gid rid of 4

Answer 5

whatever i just said..

Answer 6

Am i wrong or am i wrong?

Answer 7

don't know what that is
but yeah x=1/2

Answer 8

nvm

Answer 9

I thought anything divided by 0 is 0...

Answer 10

yes then why did you write 1?

Answer 11

Ummmmm...did i do that?

Answer 12

you should apply ln on both sides

Answer 13

Hold on let me do it again

Answer 14

nah...

Answer 15

Wait...

Answer 16

Ln(0) is undefined

Answer 17

Idk then

Answer 18

check your question

Answer 19

did you write it correctly

Answer 20

This is just a tiny part of the much longer question

Answer 21

The whole question is to find the interval where the function \[F(x) = e^{2x-1}\] concaves up and the interval where the function concaves down... and find the point of inflection...

Answer 22

Let me show you what i’ve done so far..

Answer 23

Here's what I think, \(e^x\) is always concave up and increasing. It's never concave down, so there shouldn't be any inflection points.

Answer 24

Ok but how do I mathematically prove that??? I need to solve for the x but it seems it’s not possible...

Answer 25

No solutions for x so there's no inflection points

Answer 26

Ok i see. So since there’s no solution ...what i did was...i made a data sheet and i plugged in all values from -3 to +3 into the second and i always gotta a positive y value...

Answer 27

So does that mean the graph only increases ...and never decreases ?

Answer 28

yes

Answer 29

So by that logic... there’s only an interval of increase and no decreasing interval

Answer 30

So since there’s only an increasing interval.... it should go from negative infinite to positive for all values of x correct ?

Answer 31

Because again i’m Only getting positive values for x in the second derivative...that means the original graph is only growing.. positively

Answer 32

ye

Answer 33

Okie thanks :)