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Is this set closed: A closed set is if there exists no limit points of that set that isn't an element of that set. Basically if there's a limit point that's not contained in that set, it's not closed.
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\[A = \left\{ \frac{1}{1^{2}} + \frac{1}{2^{2}} + ... + \frac{1}{n^{2}} , \forall n \in \mathbb{N} \right\}\]
I got it. The summation of 1/n^2 converges, so let that number be x, then x is limit point of A, but not in A, so it's not closed set.
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