Question

Got this wrong apparently:

can someone explain how to get to the correct answer

Answer 1

Just a sec

Answer 2

I actually got:

\[\frac{ \pi \tan(\frac{ \pi }{ x }) }{ x^2 }\]


Answer says that \(tan(\frac{ \pi }{x})\) is in the denominator

Answer 3

The question is

\[\frac{ d }{ dx }(\ln|\cos( \frac{ \pi }{ x })|\]

Answer 4

1/(cos(pi/x)) * (cos(pi/x))'
= 1/(cos(pi/x)) * (-sin(pi/x)) * (pi/x)'
= pi(tan(pi/x)) * (x^2)

lol I got the same answer as you.

Answer 5

The textbook is wrong, argue with the teacher and feel proud.