Ask your own question, for FREE!
Mathematics 12 Online
WallaPinkyWalla:

In the parallelogram, m∠KLO = 68 and m∠MLO = 61. Find m∠KJM. The figure is not to scale. 129 61 119 68

Babyplier:

do you have the image?

WallaPinkyWalla:

1 attachment
Babyplier:

Is this geometry?

WallaPinkyWalla:

yup

Babyplier:

sorry, I will try to help, but I am not the best at geometry

WallaPinkyWalla:

help!!!!!!!!

Babyplier:

I will try

WallaPinkyWalla:

help!!!!!!!

Babyplier:

I'm trying

Babyplier:

give me a sec

WallaPinkyWalla:

hurry its a timed quiz

Babyplier:

I don't really get it but go to brainly.com . That will give you the answer you neeed. SOrry I cou;don't help more

WallaPinkyWalla:

website is blocked 4 me

WallaPinkyWalla:

help!!!!

WallaPinkyWalla:

whatever thanks a loit. ill just guess

Babyplier:

I am sorry, but I don't get it. Just search your question up in brainly.com.

WallaPinkyWalla:

f off

Babyplier:

I'm done. I am never helping you again

WallaPinkyWalla:

bye

Babyplier:

bye

Skatercat:

@AngeI @Elsa213

WallaPinkyWalla:

can u help me skatercat?

Babyplier:

do you see this? she does this any time I try to help

WallaPinkyWalla:

ur a better friend than well. idk babyplier

Babyplier:

Its not my fault I am not good at geometry!

Skatercat:

without being banned i can try to halp ya

WallaPinkyWalla:

ok ty

WallaPinkyWalla:

just message me

WallaPinkyWalla:

ok i promise

Elsa213:

Thank you <3 c:

justjm:

Well here is the reasoning and yes the answer is 129° m∠KLM = m∠KLO + m∠MLO m∠KLM = 68 + 61 = 129 To find m∠KJM, first we must prove that quadrilateral LKJM is a parallelogram. This is proved because the opposite sides are parallel, as depicted in the diagram. Now, we can apply a property of parallelograms. Opposing angles are equivalent. THe opposing angle for KJM is KLM, and we know that m∠KLM is 129. Therefore, we can prove that m∠KJM is 129°, or option A

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!