Classify the triangle based on side lengths 5, 12 and 13. right acute obtuse no triangle can be formed with given side lengths
@mhchen
@Hero
and why is that
@Gdeinward @Vocaloid any ideas>
@dude
5, 12, and 13 is a Pythagorean triplet. hopefully that identifies your answer.
so right triangle?
yup! However in the future, this will not always work. As a result, you must youse the Pythagorean Inequality Theorem, if you know what that is
@justjm
Just plug 280 as area and base as 70 for a=1/2 bh
8?
yeah
So they're saying a side is congruent, and since they are parallel then they are alternate interior angles that are cut by a transversal. Then LK is shared. So it looks like SSA. is SSA ever true?
no
so that should direct you to your answer
By the way, I did geometry a while back so I might not be of best knowledge when it comes to euclidean triangle axioms and theorems.
so you're not 100% sure of this?
Sorry it's SAS
It's SAS guaranteed. Sorry I confused you with the SSA
its okay but its still false correct?
I did geometry last year
no it's true because it's congruent by SAS
it is true
yes, SSS
are you in pre-calc.
Okay I see
Took that last year buddy
oh so that is true?
Yeah it's true due to SSS
what did I say?
Yes sorry I was confused for a second
SAS
it is SAS
no what am I saying. It is SSS
They share the same side and the other 2 sides are congruent
SSS
Yes okay thats why I paused for a second lmao
Oh this is CPCTC isn't that what it's called?
I thought it is the last option
FDE is similar to CAB
not CBA?
nope
Take the second triangle and flip it so that B is on top and C is the furthest left. Now the triangles are lined up. It makes it easier
The first one, obviously
it is given that ABC is congruent to DEF and option 1 has everything in the right order
use the special right triangle rule
do you know it?
multiplying this length by the square root of 2?
to find the hypotenuse
yes
10 square root 2
I'm not sure you did it right, did you do 5 times sqrt 2 times sqrt 2?
I did \[5\sqrt{2}*2\]
yes it is 10, you said 10 times sqrt 2 before
yes because it is \[10\sqrt{2}\]
its not
plug 5√2(√2) into a calculator
(√2)^2=2, multiply by 5 you get 10!
omg see I told you im out of it today I forgot to put \[\sqrt{2}\]
sorry again
lol
try to do this one on your own
12.5?
since 25/2=12.5
yes
One face on a dice is an example of a regular polygon True False im not sure tbh
well yes it would be, when you look at a dice (cube or not) you see all sides that are regular. A regular polygon that has the same length sides and same angles
False?
check your theorms/postulates. Is there one that can prove this true?
well we automatically know because opposite sides are parallel, which does not show on the shape, which means....its true
it is true, not in that way. We have 2 angles that are congruent and the triangles share a side so what theorem/postulate shows this is true?
ASA
sorry my internet cut off but yes ASA
What grade r u in?
10th but taking geometry since im homeschooled and thats the only math im missing
I'm in 9th
basically im ahead but yeah
you're a smart 9th grader Mars
thx
wow I said a "curse" word and it turned into "mars" ight
and np
This should be easy. You know that the perimeter is 136. Set 2L+2W (length and width) equal to 136
isnt it 2(17)+2(x+3)=136 ?
yes, the equation is right
x=48
x=48
yes
I did that wrong
the area is 136. So (x+3)(17)=136. sorry about that
x=5
50?
is the answer? since when you plug 5 in it turns out that the answer is 50
yes
do the same thing as above
x=11
since (x+3)(17)=238 makes x equal to 11
correct?
Area = length x width Perimeter = length + length + width + width = 38 length = 10 10 + 10 + width + width = 38 width = (?)
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