A container of water is knocked off a 10.00–meter–high ledge with a horizontal velocity of 1.00 meters/second. Calculate the time it takes for the container to reach the ground.

A.
1.33 seconds
B.
1.40 seconds
C.
1.43 seconds
D.
1.44 seconds

Question

A container of water is knocked off a 10.00–meter–high ledge with a horizontal velocity of 1.00 meters/second. Calculate the time it takes for the container to reach the ground.

A. 
1.33 seconds
B. 
1.40 seconds
C. 
1.43 seconds
D. 
1.44 seconds

justus · Answer

What do you think?

justus · Answer

So we know that
Height h = 10 m
Velocity = 1 m/s
Using equation of motion for vertical height
$$s_{y}=ut-\dfrac{1}{2}\gt^2+h_{0}$$

$$h_{0} $$ is the initial height

u is the initial velocity

g is the acceleration due to gravity

$$s_{y} $$ is the vertical height

It is 0 at ground

Now all you have to do is put the value into the equation

$$0=0-\dfrac{1}{2}\times9.8t^2+10$$

$$4.9t^2=10 t=\sqrt{\dfrac{10}{4.9}} t = 1.43\ \sec$$