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For the function f(x) = 3(x − 1)2 + 2, identify the vertex, domain, and range. The vertex is (1, 2), the domain is all real numbers, and the range is y ≥ 2. The vertex is (1, 2), the domain is all real numbers, and the range is y ≤ 2. The vertex is (−1, 2), the domain is all real numbers, and the range is y ≥ 2. The vertex is (−1, 2), the domain is all real numbers, and the range is y ≤ 2.
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yes xD f(x) = a(x-h)^2+k vertex is (h,k) here here -h=-1 so h=1 and k=2 so vertex is (1,2) and domain is always all real numbers for quadratics, the range will be determined based on the sign of 'a' (positive here). So it would be y≥2 because it increases upward
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