Question

points (3,2) and (4,7) and horizontal asymptote at y=4

Answer 1

The degrees are the same so leading coefficient is 4/1 which is 4

Answer 2

2=(4(3)+b)/(3+c) >> 2= (12+b)/(2+c) >> 4+2c = 12+b >> b-2c = -8
7= (4(4)+b)/(4+c) >> 7 =(16+b)/(4+c) >> 28+7c = 16+b >> b= 7c+12
7c+12) -2c = -8 >>>> 5c=-20 >> c = -4
7(-4)+12 = -16 = b
(4x+(-16))//(x+(-4))

Answer 3

brb

Answer 4

2=(4(3)+b)/(3+c) >> 2= (12+b)/(2+c) >> 4+2c = 12+b >> b-2c = -6
7= (4(4)+b)/(4+c) >> 7 =(16+b)/(4+c) >> 28+7c = 16+b >> b= 7c+12
7c+12) -2c = -6 >>>> 5c=-18 >> c = -18/5
7(-18/5)+12 = -186/5 = b
(4x+(-186/5))//(x+(-18/5))

Answer 5

still wrong?

Answer 6

must be something esle

Answer 7

2=(4(3)+b)/(3+c) >> 2= (12+b)/(3+c) >> 6+2c = 12+b >> b-2c = -6
7= (4(4)+b)/(4+c) >> 7 =(16+b)/(4+c) >> 28+7c = 16+b >> b= 7c+12
7c+12) -2c = -6 >>>> 5c=-18 >> c = -18/5
7(-18/5)+12 = -66/5 = b
(4x-(66/5))//(x+(-18/5))