Question

help ...

Answer 1

\[x = \log_{a}bc => bc = a^x , y = \log_{b}ca => ca = b^y , z = \log_{c}ab => ab = c^z ,find 1+abc = ? \]

any help - idea ? thank you !

Answer 2

find 1+abc = ?

Answer 3

I think your question got cut off at the end

Answer 4

oh nvm

Answer 5

Three equations & three unknowns, what's the problem?

Answer 6

bc = a^x => b = (a^x)/c
ca = b^y so ca = [(a^x)/c]^y
ab = c^z so a[(a^x)/c] = c^z

bc*ca*ab = (a^x)(b^y)(c^z)

(abc)^2 = (a^x)(b^y)(c^z) divide both sides by (abc) and will get

abc = [a^(x-1)][(b^(y-1)][c^(z-1)]

- are these above wrote correct ?

Answer 7

@Ultrilliam your opinion about this please ? thank you

Answer 8

write every logarithm with a common base and then rename loga, logb, logc to l, m, n it'll make things easier