The rectangle shown below had length 20 meters and width 10 meters. If four triangles are removed from the rectangle as shown what will be the area of the remaining figure
You should include the rectangle if you want an answer.
|dw:1584168576073:dw| do you think it like this above posted image ?
For finding the remaining area, we have to subtract the four triangles area from the rectangle area. Area of rectangle is: \[20 \times 10 = 200 \, m^2 \] Now: From the figure, we can see that on both sides (left and right ) two triangles form another triangle whose base is 10 m. and height is also 10 m. So: The area of each such triangle is: \[\frac{1}{2} \times 10 \times 10 = 50 \, m^2 \] Area of such two triangles (left side and right side ) is: \[2 \times 50 = 100 \, m^2 \] Hence: The area of remaining portion is: \[200 - 100 = 100 \, m^2 \]
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