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Mathematics 6 Online
sutralotv12:

PLEASE HELP!!! write a quadratic function, h(t), that shows the height, in feet, of the soccer ball, t seconds after it was kicked. Use the general equationh(t)= - 16t^{2} + v_{0}t + h_{0} where v_o is the initial velocity and h_o is the initial height. Show how you got the x-intercepts, the vertex's as well as graph it. How long was the soccer ball in the air?

darkknight:

I dont get it, can you make up your equation_

sutralotv12:

Idk, it doesn't give me another equation for it

darkknight:

is there a picture?

sutralotv12:

I'll give you one

darkknight:

a picture is needed for this i guess,

darkknight:

like associated with the problem is what i meant

sutralotv12:

This isn't the full of it but here you go

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darkknight:

I gtg, sorry. Ask someone else to help you. I will get back to you later maybe

sutralotv12:

ok, no problem

darkknight:

Can you send the rest of the question, by any chance?

sutralotv12:

yeah

sutralotv12:

here is one and I'll send the last bit right now

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sutralotv12:

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Hero:

I wonder what is in the "show your work" part.

sutralotv12:

they are all blank

Hero:

Says to click that first before writing the quadratic equation.

darkknight:

yeah, thats why there was no problem

Hero:

then it says "of THE soccer ball" which implies they presented you with a problem scenario to begin with. I don't see where you have posted the initial problem statement.

sutralotv12:

i am so sorry there was fine print I was missing, I apologize for wasting your time, it had an initial velocity of 96 ft per second. I didn't see the fine print right above it

Hero:

Can you just please screenshot the initial problem statement?

Hero:

I don't know why you've posted everything else but avoided posting the initial problem statement when that is the most essential piece of this puzzle to post.

sutralotv12:

ok

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Hero:

Yes, now we know essential things like "The ball was kicked vertically while on the ground"

sutralotv12:

I'm sorry. I didn't see that part

Hero:

Yes because we now know that \(h_0\), the initial height of the ball at \(t = 0\) is also zero since the ball is on the ground and not on a roof.

Hero:

We also now know that \(v_0\) the initial velocity is 96 feet per second.

Hero:

Knowing all this information, we are able to set up the quadratic function.

Hero:

If \(v_0 = 96\) and \(h_0 = 0\) how do you suppose we might write the expression for \(h(t)\)?

sutralotv12:

plug in 96 for \[v_0\] and 0 for \[h_0\]

Hero:

Correct and what would that look like if we did that? Can you write out the entire function?

sutralotv12:

that would look like h(t) = -16t2 + \[96t + 0\]

Hero:

If we're using correct notation it would be \(h(t) = -16t^2 + 96t + 0\). If you're not familiar with LaTeX just put a caret between the t and the 2: h(t) = -16t^2 + 96t + 0

sutralotv12:

oh, right forgot about that

sutralotv12:

alright I got the equation plugged in and I assume I would treat it like a regular quadratic function and find a, b, and c, and then solve using that?

darkknight:

a, b and c is already given. You can determine that from the function

sutralotv12:

right but I mean solve using a b and c

darkknight:

The problem is asking you to write a function and you have already done that. So you are done

darkknight:

Or did you need anything else?

sutralotv12:

there is more, I have to find x intercepts, vertex, then graph, and then find how long the ball was in the air

darkknight:

oh okay. To find the x-intercepts you can use the quadratic formula

darkknight:

remember to find the x-coor of the vertex you can use the formula (-b/2a) and then plug that in for y

sutralotv12:

ok

darkknight:

and then ur basically done

darkknight:

graph it then find the time when the ball hits the ground, or the second x-intercept. Since we are talking about t then the time it takes for the ball to drop is how much time it was in the air because we started from 0

sutralotv12:

it says t=(6,0), would that be x intercept 1?

darkknight:

where does it say that?

darkknight:

oh you mean that the x-intercepts are at 6,0 and 0,0

darkknight:

good job

sutralotv12:

I'm using mathway for the quadratic formula since I don't got a lot of time

darkknight:

so how long was that ball in the air?

darkknight:

no im pretty sure it says that ur x-intercept is at 6

darkknight:

Now find the time it stayed in the air?

sutralotv12:

150 seconds?

darkknight:

why?

darkknight:

a visual might be easier to use to explain

darkknight:

hold on, ill graph this using desmos then show u

darkknight:

so as you can see here, the 2 x-intercepts

darkknight:

how much time does it take the ball to drop is the same as how long it is in the air Can you figure it out?

sutralotv12:

oh, six seconds

sutralotv12:

dang, that is one high and steep kick

darkknight:

ye lol

darkknight:

u got it, keep it up :0

sutralotv12:

thanks

sutralotv12:

wait, can someone show me the steps to solving this with quadratic formula?

darkknight:

oh yeah sorry

darkknight:

so once you find the x-intercepts that is when the ball hits the ground right?

darkknight:

so the x-intercepts were 6 and 0 and it takes 6 seconds to drop

darkknight:

plug in the numbers

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