3√8w^2 ... Solve this.
What are we trying to do
try to solve it
?
simplify?
\[\sqrt[3]{8w ^{2}}\]
yes
oh ok, so what you do is that can take the W^2 out of the square root. do you know what i mean?
like the w^2 when you square root is w
2\[\sqrt[2]{8w ^{2}}\]
sorry, the I meant to put a 3 with the radical
\(\color{#0cbb34}{\text{Originally Posted by}}\) @TheRobin 2\[\sqrt[2]{8w ^{2}}\] \(\color{#0cbb34}{\text{End of Quote}}\) Its not sqaure root, its cubed
and simplifying the sqrt 8 u can rewrite as 4 times 2 under the square root then take the square root of 4 and get 2 times sqrt of 2
Ik I meant to put three
i think i got it
\[2w ^{\frac{ 2 }{ 3 }}\]
no
i searched in mathway, its correct
I also used mathway and I got different answer
so you have 3 times sqrt of 8w^2 right then you can take the w out like how I told u and have 3w times sqrt of 8. You can simplify the 8 into 4 times 2 and then take the 4 out getting 6w times sqrt 2
Use properties of exponents
your answer is right
my answer that i got was \[2w ^{\frac{ 2 }{ 3 }}\]
whose?
ill even snip it
what math is this, algebra 1?
well for my brother
yea, he needs help
this is your brother's problem? can't u help him then?
im too lazy, and i practically dont understand
hold up, do you understand what I did for that problem?
all of them?
Cool, that is the Rational Exponents, not simplified form, which one does it need?
already did 1 2: distribute the exponent that is to the power of 3 over all the individual terms, like the 8 is going to be 2, and the w^2 is going to be w^2/3 so the new eqn becomes 2(w^(2/3))
3: simplify the 8 like in the step above well it leads to the same answer as 2 xD
4) is also 3 but the 8 is rewritten so it is also the same
oh wait a minute, these are all steps to the same problem
When you realize...
OMG, why??? you said it was 3 times 8w^2 first not cube root
Where do you see that?
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