precalc
Notice that you have the angular speed \(12\textrm{ RPM}\). This means that every minute, the wheel performs \(12\) full turns, which corresponds to an angle of \(12 \times 360^\circ = 4320^\circ\). Therefore, we can write the angular speed as: \(12 \textrm{ RPM} = \dfrac{4320^\circ}{60\textrm{ s}} = 72^\circ/\textrm{s}.\) From the picture, we see that the angle that separates \(P\) from the top is \(\theta + 90^\circ\). By considering that we know it takes Tiff \(1.3 \textrm{ s}\) to go from \(P\) to the top, can you now see how to get the answer?
oh, what about question c
From what I wrote above, you already have the angular speed. Since you know that the seat flew off after \(6\textrm{ s}\), can you know see how to calculate the angle with respect to the initial position \(P\)?
thanks DuarteME
No problem! \(\ddot{\smile}\)
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