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Determine ∆G° for 2 NO₂(g) → N₂O₄(g) at 25°C. NO2 = 51.3 N2O4 = 97.8
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Are those values \(∆G_f°\) values?
Yes they are.
Use the formula \[∆G°=\sum ∆G_f° _\text{products}- \sum ∆G_f°_\text{reactants}\] Don't forget to consider stoichiometry. For NO2, you have to consider the '2' in the reactants (i.e., multiply the free energy of formation by 2, because it's 51.3 kJ/mol of reactant or product, and here you have 2 mols). Units are in \(kJ/mol_{rxn}\)
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