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Q(t)= mathcal Q 0 e^ -kt may The function be used to model radioactive decay . Q represents the quantity remaining after tyears;k is the decay constant, 0.00011. How long, in years, will it take for a quantity of plutonium-240 to decay to 25% of its original amount? O O 9,450 years 3, 150y years C. 12, 600 years D. 1, 5 years
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@ramen
To solve this we can clear up some junk. So our equation is Q(t) = Qo e^-kt plug in 0.00011 for k and the initial amount for Qo is 1, which is the starting value. 25% = 1/4 So 1/4 = 1e^-0.00011x Use a graphing calculator to estimate
If you want to do it the non-graphing calculator way, Use natural log
If you want to learn how to do it the natural log way, Ask away!
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