If you tripled the slant height and radius of a cone, what would be the formula to find the modified surface area? A. 2004-06-01-03-00_files/i0120000.jpg B. 2004-06-01-03-00_files/i0120001.jpg C. 2004-06-01-03-00_files/i0120002.jpg D. 2004-06-01-03-00_files/i0120003.jpg
Hai welcome to QuestionCove c: Those files didnt load so may you please attach any pictures?
A) \[\frac{ 1 }{ 3 }\pi*rl + \frac{ 1 }{ 3 }\pi*r^2\] B) 6*pi*r*l + 6*pi*r^2 C) 12*pi*r*l + 9*pi*r^2 D) 9*pi*r*l + 9*pi*r^2
Oh god Voca I prefered it when I couldnt see it
Yeah I dunno how to explain this, you got it e.e
I mean you just gotta take the SA formula for a cone given the slant height and radius SA = \(\pi*r^2 + \pi*r*l\) where r is the radius and l is the slant height since the problem specifies that the slant height and radius are tripled, simply substitute 3r and 3l into the equation and find SA
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