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The following geometric sequences represent the population of two bacterial cultures at the 1 hour mark the 2 hour mark the 3 hour mark and so on culture A starts with more bacteria but culture b has a ratio of increase that is larger which culture will have the greater population at the 18 hour mark
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\[A = A_{0}(r)^{t}\] where A0 is the initial population, A is the final population, r is the common ratio, and t is time (years) to find r for a sequence, simply take any value in the sequence and divide it by the previous value find r for both cultures A and B then, using the common ratio r, and the initial value A0 for each culture, let t = 18 and plug these values into the formula to find the final population A
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