The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of θ? Make sure to show all work.
@darkknight
whoops. I drew that wrong. HOld up
its okay :)
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\[\sin=oppo/hypo.\] \[\cos=adj./hypo.\] \[\tan=oppo./adj.\]
sin= \[\frac{ \sqrt{2} }{ 2 }\]
is that correct?
or is that cos?
one is negative and one is positive, i know that
Actually all you have to do is that sin(theta) = y/r cos(theta) = x/r And tan(theta0 = y/x
r is \[\sqrt{x^2+y^2}\]
Where x is 1 and y is -1
so you'd use the pythagorean theorem right?
Yes, to find for tan(theta) = y/x
so confirm my answers
sin=\[\frac{ \sqrt{2} }{ 2 }\] cos= \[-\frac{ \sqrt{2} }{ 2 }\] tan= -1
correct?
No.
cos and sin have to switch?
sin is the y value. You flipped sin and cos
lol ok. i thought so
thanks! i have one more. can you help me?
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