Geraldine is picking a four-digit password by using the digits 0 through 9. She can use each digit only once. How many different passwords are possible? 34 40 5,040 10,000
ok, this one would be like if you had four spinners, each one with numbers 1 - 9 on them.
When dealing with a larger amount of outcomes and when counting the number of possibilities, you would multiply.
k
*0 - 9
So what is the largest code they can make?
um.....D
I mean what numbers are the largest in the 4-digit code?
her largest possibility.
C
9876
k
so it has to match?
no
ok?
so, do you know how to calculate the probability?
no
\[\frac{ n! }{ n-r! }\]
So n is the amount of numbers r is the total numbers needed
You could do it using the method @Aqual described or apply permutations She has to choose 4 digits from 10 total, and order matters. This equates to \(\text{nPr(10,4)}\). Nothing else needed at this point. Just calculate it using the formula for permutations
Oh wait sorry I interrupted you @Aqual, I didn't see you were explaining with permutations too. You can carry on.
im back
ill try to finish
k
back
k
so if you filled it in, it would look like \[\frac{ 10! }{ 10 - 4! }\]
so 6?
no
the factorial affects it
k
do you know what a factorial is?
yes
so I have to divide
So 5,040
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