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Mathematics
Alexis15:

PLEASE HELP: Hillary is using the figure shown below to prove Pythagorean Theorem using triangle similarity: In the given triangle ABC, angle A is 90° and segment AD is perpendicular to segment BC. The figure shows triangle ABC with right angle at A and segment AD. Point D is on side BC. Which of these could be a step to prove that BC^2 = AB^2 + AC^2? (A)By the addition property of equality, AC^2 plus AD^2 = AB multiplied by DC plus AD^2. (B) By the addition property of equality, AC^2 plus AD^2 = BC multiplied by DC plus AD^2. (C) By the addition property of equality, AC^2 plus AB^2 = AB multiplied by DC plus AB^2. (D) By the addition property of equality, AC^2 plus AB^2 = BC multiplied by DC plus AB^2.

Alexis15:

darkknight:

What do you think it is?

darkknight:

Well as we can see. We can prove this with Pythagorean theorem. Which doesn't seem to be an answer choice.

Alexis15:

i think it is A

darkknight:

does it mean squared when you say BC2?

darkknight:

Bc^2?

Alexis15:

yea BC^2

darkknight:

a seems besides the point because we have to prove BC^2 = AB^2 + AC^2 true,

darkknight:

hold on, lemme think about this.

Alexis15:

ok

darkknight:

So if you notice, for every answer choices such as AC^2 plus AD^2 = AB multiplied by DC plus AD^2. You can simplify to AC^2 = (AB)(DC) which we can substitute into the Pythagorean theorem (well the correct one) to see which answer choice is correct

darkknight:

So for the second answer choice it would be C^2 = BC)(DC

darkknight:

if we simplify it is what I mean

darkknight:

Oh, I was being dumb. This has to do with proportions.