Question

equation log7(3x^3+x)- log7(x)=2

Answer 1

logarithm rules:

log(M/N) = log(M) - log(N)

applying this rule to your problem, you can re-write the difference of logs as a quotient

log7(3x^3+x)- log7(x)=2

becomes

log7([3x^3+x]/x]) = 2

re-write both sides as exponents of base 7, to get rid of the log7. then solve for x by cross multiplying.