Question

Can someone help me with these 5 math questions?

Answer 1

post em

Answer 2

oof hold up i can recommend someone give me a sec

Answer 3

ok thanks!

Answer 4

@Hero @Vocaloid

Answer 5

@Shadow @Ultrilliam

Answer 6

in general, a number in scientific notation will take the form

a * x^(n)

where \[1 \le a < 10\]
and n is a positive integer

so,

1.0 * 10^(2) would count as scientific notation, but 11 * 10^2 would not. (11 * 10^2 would need to be re-written as 1.1 * 10^3)

Answer 7

so, let's look at your first problem:

T = \[2\pi \sqrt{\frac{ 4.5*10^{-2} }{ 2.0*10^{3} }}\]

start by simplifying the expression inside the radical, using your exponent rules

then apply the radical by taking the square root of your previous result

finally, since you have a 2pi on the outside, multiply the previous result by 2pi

let me know what you get from that, or if you're still confused by any steps

Answer 8

I got 0.0298 or 2.98* 10^-2

Answer 9

good, that's what I got too (doesn't say anything about sig figs or rounding so I guess we can just round to 2 digits like you did)

Answer 10

for the next one, you can repeat the same process (multiply the numbers out, then convert to scientific notation by moving decimal places as necessary). let me know what you get or if you're getting stuck

Answer 11

Could you help me with the units?

Answer 12

oh yeah, sure

notice how kg and kg cancel out so we're left with

\[\frac{ 1 }{ \frac{ 1 }{ s^{2} } }\]

if we re-write this fraction as a multiplication problem (change the division to a multiplication sign, then flip the second fraction), we get

\[\frac{ 1 }~{ \frac{ s^{2} }{1 } }\] or just s^2

Answer 13

however, since that's inside the square root ---> take the square root to get s

Answer 14

Ok thanks! I got it now. For #2, would the ^2 be a part of the m/s?

Answer 15

Without the units, for #2 I got 6.96*10^6

Answer 16

yes, I got that value too

for the units, yes, the ^2 gets applied to the m/s
therefore it becomes ---> m^2 / s^2
with kilograms combined, it becomes (kg m^2) / s^2

Answer 17

Ok so does that mean the units for #2 are (kg m^2) / s^2?

Answer 18

yes

Answer 19

Ok, I'm going to try question 3

Answer 20

I got to (9x10^-9) * (9.6*10^-17)N, but I don't think that's right :/

Answer 21

you're on the right track, however, remember that it's (0.32)^2 not just 0.32, so you'll need to divide by 0.32 again

your units are right (N)

Answer 22

Ohh, okay, that makes sense

Answer 23

3*10^-16?

Answer 24

hm, I got something a bit different

this part was right
(9x10^-9) * (9.6*10^-17),

you just need to divide this by 0.32
---> (9x10^-9) * (9.6*10^-17) / 0.32 = ?

Answer 25

2.7*10^-24?

Answer 26

yup, so 2.7 * 10^(-24) N is your solution

Answer 27

Alright thanks!

Answer 28

I'll try 4 and 5 on my own and let you know if I need any help! But thank you so much!

Answer 29

sure, just lmk if you're having trouble