Question

A bus is traveling with a uniform acceleration of 2.75 meters/second2. If the initial velocity of the bus is 16.5 meters/second, what will its velocity be after 9.00 seconds?
A.
27.8 meters/second
B.
41.3 meters/second
C.
58.0 meters/second
D.
408 meters/second
E.
57.4 meters/second

Answer 1

Use your kinematics equations

vf=vi−at

a=2.75m/s2
vi=16.5m/s
t=9.00s
vf=vf

Plug in and solve for vf

Answer 2

so the answer is ?

Answer 3

I told you how to solve it

Answer 4

I dont have nothing to solve it sorry. thats why im asking

Answer 5

ok hold on

Answer 6

thanks

Answer 7

You could make a table that looks like this:

Time Velocity

0 16.50 m/s (This is your starting point)
1s 19.25 m/s
2s 22.00 m/s
3s 24.75 m/s
4s 27.50 m/s
5s 30.25 m/s
6s 33.00 m/s
7s 35.75 m/s
8s 38.50 m/s
9s 41.25 m.s

Answer 8

this are the answers:
27.8 meters/second
B.
41.3 meters/second
C.
58.0 meters/second
D.
408 meters/second
E.
57.4 meters/second

Answer 9

that was wrong

Answer 10

is one of them a.b.c.or d

Answer 11

I just didnt round

Answer 12

I mean rounded up

Answer 13

because its 41.25 you use the 5 in .25 to make it .3

Answer 14

i put that one. me and my son is doing plto with the books for school and i cant answer half of the questions

Answer 15

A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the water at the bottom of the well 5.00 seconds after being dropped from the tower. Calculate the depth of the well. Given: g = -9.81 meters/second2.
A.
22.5 meters
B.
50.7 meters
C.
100 meters
D.
110 meters
E.
152.45 meters

Answer 16

A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the water at the bottom of the well 5.00 seconds after being dropped from the tower. Calculate the depth of the well. Given: g = -9.81 meters/second2.
A.
22.5 meters
B.
50.7 meters
C.
100 meters
D.
110 meters
E.
152.45 meters