Question

The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X:

The figure shows a circle with points A and B on it and point C outside it. Side BC of triangle ABC intersects the circle at point X. A tangent to the circle at point A is drawn from point C. Arc AB measures 152 degrees, and angle CBA measures 64 degrees.

What is the measure of angle ACB?

32°
6°
24°
12°

Answer 1

@Vocaloid pls help

Answer 2

@silvernight269 pls help

Answer 3

@countrygirl68 pls help

Answer 4

@BlasiannPrincess1 pls help

Answer 5

Do you have a diagram of the figure?

Answer 6

Of course yeah let me post it

Answer 7

First find out what angle A measures to

Answer 8

Sorry but I don't know how to do that, if you could tell me how to do it?

Answer 9

Hello?

Answer 10

@countrygirl68 ?

Answer 11

I’m working with it rn

Answer 12

@countrygirl68 alr thank you

Answer 13

@Kitkit please help

Answer 14

im rlly good at trig but i can only try to help TwT

Answer 15

Lmao whatever you can do would be great

Answer 16

You first want to get the measure of arc AX

This is straightforward as you already know angle B.
AX = twice of angle B


Once you know AX you can simply subtract the smaller arc from the larger arc
In this case, 152 - m\(\angle\)AX = m\(\angle\)C

Answer 17

So then the answer would be 24? Thank you so much for the help!

Answer 18

Yeah

Answer 19

@dude could you please help me with one other question?