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Mathematics 15 Online
ashten0219:

Compute the permutation. How many positive integers of 3 digits each can be formed with the digits 1, 8, 9, 2, 7, 6, 4, and 3, if no digit is repeated in a number? the answer is 336. How?

Vocaloid:

You should probably start reviewing old problems, because the concept has been similar each time there are 8 possibilities for the first digit 7 possibilities for the second digit 6 possibilities for the third digit

SemiDefinite:

8P3

ashten0219:

omg im so dumb thx voca

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