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ashten0219:
Compute the permutation. How many positive integers of 3 digits each can be formed with the digits 1, 8, 9, 2, 7, 6, 4, and 3, if no digit is repeated in a number? the answer is 336. How?
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Vocaloid:
You should probably start reviewing old problems, because the concept has been similar each time there are 8 possibilities for the first digit 7 possibilities for the second digit 6 possibilities for the third digit
SemiDefinite:
8P3
ashten0219:
omg im so dumb thx voca
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