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Chemistry
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Calculate the specific heat (J/g°C) for a 13.5 g sample of zinc heated from 24.2°C to 83.6°C that absorbs 312 J of heat.
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q = mC(Tf-Ti) where m is mass (13.5g), C is specific heat (which you'll solve for), Tf is final temperature (83.6°C), Ti is initial temperature (24.2°C), and q is heat (312J). plug in the appropriate values and solve for C.
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