A coffee mixture has beans that sell for $0.20 a pound and beans that sell for $0.68. If 120 pounds of beans create a mixture worth $0.54 a pound, how much of each bean is used? Model the scenario then solve it. Then, in two or more sentences explain whether your solution is or is not reasonable.
@Vocaloid
@dude
@shadow I'm going to bed soon (early shift tomorrow), would you mind taking a look at this
So this problem is about a system of equations. We basically need to write two true equations for this scenario, and using those equations, solve for the unknown variables.
Let x = the weight of the first bean in pounds Let y = the weight of the second bean in pounds The first equation we can write is: \[x + y = 120\] This is because if the total mixture used is equal to 120, then we can say that its ingredients, x and y, constitute that total weight.
Do you see the idea?
yes
We can actually make this a bit more efficient. Another way we can write this is that. \[y = (120 - x)\] Now for the second equation: \[0.2x + 0.68y = 0.54(120)\] What we're saying here is that the total pounds of x beans times its price + the total pounds of y beans times its price, = the total price of the mixture of beans times the total pounds of x + y beans.
Using the y equation, we can make it so there's only one variable, and that we're able to solve: \[0.20 + 0.68(120 - x) = 0.54(120)\]
Do you think you got it from here?
Fixed an error: \[0.20x + 0.68(120 - x) = 0.54(120)\]
x=35
I got the same
About this being reasonable, I think it would be right? 35
Yes
I think the answer to this question is reasonable. 35 is reasonable because it is not too expensive and not too cheap, the perfect price.
Would this be ok to sum it up
I think they're talking more so about your problem solving / thinking than the price of beans.
okay thank you i have one more question that needs to be checked do you want me to open a new post
Sure
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