In rhombus ABCD, diagonals AC and BD intersect at point E. If AE=5cm and BE=12cm, what is the length of AC?
|dw:1604003248591:dw| From the diagram, we can see that the length AC = AE + EC we also know that the length of AE = EC AC is AE+EC and we know that AE is 5cm and that EC=AE, so EC is also 5cm. So the value of AC = 5cm + 5cm = ?
yeah, good job. does it make some sense now?
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