A bet between friends results in a coin toss. If the coin is tossed from a height of 1.3m and had a hang time of 1.7s. What was the initial velocity of the coin? How high did the coin go?

Question

A bet between friends results in a coin toss. If the coin is tossed from a height of	 1.3m and had a hang time of 1.7s. What was the initial velocity of the coin? How high did the coin go?

jhonyy9 · Answer

@imqwerty can you solve this ?

imqwerty · Answer

|dw:1604255090744:dw|

use these equations.

unknown102920 · Answer

yea umm thankkuuu but the thing is i literaly have no idea how to do this problem at all like can u explain hoe to do it and show how u got the answer

unknown102920 · Answer

how*

imqwerty · Answer

|dw:1604256923575:dw|

imqwerty · Answer

the yellow circle is the ball, which is thrown upwards with an initial velocity of $u$ m/s (an unknown value) and from a height of 1.3m

imqwerty · Answer

it travels a distance $x$ meters and then finally reaches the top point (marked as red) where it's velocity drops to 0 and then the ball starts falling down.

imqwerty · Answer

assume $t_1$  = time taken to reach top most point from initial position
$t_2$ = time taken to drop to the initial position from top most position
$t_3$ = time taken to further drop from initial position to ground

imqwerty · Answer

you know that:  $t_1 + t_2 + t_3 = 1.7$

use this and everything that i told above  to figure out $t_1$ .

once you have $t_1$ it's easy to find $u$

imqwerty · Answer

hint: $t_1 = t_2$