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Mathematics 9 Online
dontsaymyname:

Math question

dontsaymyname:

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darkknight:

Okay, first we identify the vertex. Use the formula -b/2a to find the x-coordinate for the vertex, then plug what u get back in for x in the equation to find the y-coor. for the vertex and then you'll have ur vertex

darkknight:

Now the axis of symmetry for a parabola will just be what x equals at its vertex, because in a parabola the vertex divides the parabola in half, by half I mean like this |dw:1604515359974:dw|

darkknight:

Now the maximum or minimum value can also be determined. So we look at the A value for the parabola. If a is positive, then the function (quadratic) would be upwards like this. which would mean that u have a minimum |dw:1604515465692:dw| and if A is negative then it would be pointing downwards like this|dw:1604515499446:dw| which would mean u have a maximum

darkknight:

Now once u know whether it is a maximum or minimum, the y coordinate of the vertex is your maximum or minimum

darkknight:

The domain of any quadratic is from \[(-\infty, \infty)\] in interval notation, or just from -infinity to infinity, The range on the other hand depends on which way the quadratic is pointing. If the quadratic is pointing up, then the range is from that point to infinity. If the quadratic is pointing down (remember the symbol of A affects it, where A is the coefficient in front of the x^2 term) then the range is from -infinity to that point. Since we have a negative, then our range would be from -infinity to the y-coordinate of the vertex

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