Question

1. The axis of symmetry for the function y = -x2 - 10x + 16 is x = -5. What are the coordinates of the vertex of the graph?

Put -5 in for x and solve for y

Answer 1

This is pretty straightforward

They gave you a critical hint onto what you should be doing: `Put -5 in for x and solve for y`

That said, the equation they are giving you is: \(y = -x^2 - 10x + 16\)

\(y = -(5)^2 - 10(5) + 16\)

Do you know how to solve this?

Answer 2

not really

Answer 3

i tryed that and it sayed it was wrong

Answer 4

i got 1 more attempt

Answer 5

Oh I missed the -5

\(y = -(-5)^2 - 10(-5) + 16\)

Hmm did you do -5 or 5?

Answer 6

-5

Answer 7

What did you get when solving for y?

Answer 8

i got -9

Answer 9

Hmm that doesn't look right

You should try it again. If you'd like you can show your process here and I can help you noting your mistakes

Answer 10

ok

Answer 11

Tbh I would do what’s in the parentheses 1st

Answer 12

(-5)² =-10 then (-10) -(-10)(-5)

Answer 13

plus 16

Answer 14

and i got -9

Answer 15

Ah theres your mistake

-5^2 is not -5* 2

-5^2 is -5*-5

Answer 16

oh

Answer 17

Lol it’s exponents

Answer 18

(-25)(-10)-(-10)(-5)+16 then i got -34

Answer 19

Ay i see what u did there but again honestly I would do what’s in the parentheses first and then rewrite the problem over with what u u got doing the parentheses

Answer 20

i did that and still got -34

Answer 21

y=-25-50+16 is what I got lol

Answer 22

then you get -59

Answer 23

441204, careful

\(y = -(-5)^2 - 10(-5) + 16\)

Theres a negative infront of the \(-5^2\)

\(y = \color{red}{-}25 - 10(-5) + 16\)

Then you also have to account for -10 * -5 both being negative

\(y = -25 +50 + 16\)

Answer 24

y=41 ?

Answer 25

Yes that should be your y value

Answer 26

They are asking for the coordinate now

Answer 27

i dont even know how to find that

Answer 28

No more steps to this

Just write the x and y as (x, y)

Answer 29

so -5,41

Answer 30

Yeah (-5, 41)

Answer 31

thank u