Question

Can some1 help me pleaseeeeeeeee Its Math

Answer 1

What is it

Answer 2

what is it

Answer 3

Its in the attachment :/

Answer 4

im dum so probs not

Answer 5

I can't see the attachment, can you type it out?

Answer 6

I'm dm u it cuz its a lot

Answer 7

For some reason, I can't see photos in general

Answer 8

hold on, ill get to you in an hour approx. @darkknight

Answer 9

Ok, thanks

Answer 10

also @ramen if/when you are free

Answer 11

2+2 is 4-1 thats 3 quickmath

Answer 12

huh @jbpeppers809

Answer 13

@darkknight Hey jw if ur able to help? I have more questions, but I cant post them with this open.

Answer 14

si, here now

Answer 15

Are you allowed to use a graphing calculator? jw

Answer 16

Yes

Answer 17

I'm going to close this bc i need some help with other questions, is that okay?

Answer 18

alright, u need hlep on this one still or?

Answer 19

Yes I do, please and thank you

Answer 20

Okay, so we have only need 3 points to determine the equation of the quadratic.
Lets pick the points 30,29)
40,22)
and (50,17)
Now we need to know this formula \[ax^2+bx+c = y\]
We can plug in the above x and y-coordinates into this equation and solve for a, b and c

Answer 21

So our 3 equations will be
\[a(30)^2+b(30)+c = 29\]
\[a(40)^2+b(40)+c = 22\]
\[a(50)^2+b(50)+c = 17\]

Answer 22

Now we can do some simplifying
\[900a+30b+c =29\]
\[1600a+40b+c =22\]
\[2500a+50b+c =17\]

Answer 23

Now we have to solve for the variables, lets start with eliminating c,
so
900a+30b+c=29

1600a+40b+c=22

Applying subtraction
-700a -10b = 7

Now we can rearrange ^

Answer 24

Now lets take
these 2 eqns

1600a+40b+c=22

2500a+50b+c=17
And eliminate c
So we get

-900a-10b = 5
so -900a = 5 + 10b
or a = (5+10b)/-900

Answer 25

@dontsaymyname

Answer 26

I'll try, thank you soooooooooooooooooo very much @darkknight

Answer 27

We had this eqn previously -700a -10b = 7
Plug in (5+10b)/-900 for a
And then
\[−700((5+10b)/−900)−10b=7\]

simplifying
\[((7(5+10b))/9)−10b=7\]

so
\[(35/9+70b/9)−10b=7\]

Can you solve for B?

Answer 28

Anyways, once you get b, plug into a = (5+10b)/-900 OR -700a -10b = 7
You should get the same a value if u try on both. Then plug in both a and b and solve for c

Answer 29

Okayyyy I'll try that, thanks again