Question

Math Question, please help!!! o_o Picture Attached

Answer 1

A?

Answer 2

Yeah but I need an equation lol thxs tho :)

Answer 3

Idk.

Answer 4

Oh, Np.

Answer 5

have you asked darkknight? he's pretty good

Answer 6

He's looking lol, but he might be busy

Answer 7

oh yh lol there he is

Answer 8

Alright, 3 points, you can get a quadratic function. Any quadratic function goes through 3 points. What I mean is that a quadratic function can be drawn through any 3 points. So your answer is a Quadratic model does exist.

Answer 9

Now to find the equation of the quadratic, you need to solve for a b and c, in the form ax^2+bx+c

Here is how we do that
So
we plug in values of x into x, and the corresponding y values into y.

Answer 10

So...
\[a(0)^2+b(0)+c = 2\]
\[a(2)^2+b(2)+c = -2\]
\[a(-1)^2+b(-1)+c = -5\]

Answer 11

Those above are your three equations, what do we want to do next?

Answer 12

Simplify?

Answer 13

yes, that is what we do next
So can you simplify the above equations for me?

Answer 14

Sure 1 sec

Answer 15

C=2
C= -2 - 4a - 2b
C= -5 - a + b

Answer 16

alright, so now we can use substitution

we can say that 2 = -2-4a-2b
so then 4= -4a-2b
we can also say 2 = -5 -a+b
so then 7 = -a+b
We have 2 equations
7=-a+b is the same as 14 = -2a+2b
Now we have 14 = -2a+2b
and 4 = -4a-2b
We can add _______________-
18 = -6a
And now a =-3

Answer 17

Super srry i gotta go, but ill login on my phone super srry Thx u smm again

Answer 18

Now we know
C= -5 - a + b

We know c=2 and a=-3
So then
2 = -5 - (-3) +b

Answer 19

Can you solve for b?

Answer 20

@dontsaymyname

Answer 21

Alright, 2 = -5 - (-3) +b

B would just be 4. So a = -3, b = 4 and c=2
plug into ax^2 + bx +c = y

Answer 22

if u are stuck anywhere ask away!

Answer 23

Omg, thank you so much, @darkknight, so very sorry, I had to help cook and then my phone died, but I thank you so very much for helping me out multiple times like frfr, I might need more help later tonight, r u good with consumer math? Again thx u smm

Answer 24

np,