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An acrobatic airplane performs a loop at an airshow. The centripetal acceleration the plane experiences is 14.7 m/s2. If it takes the pilot 45.0 seconds to complete the loop, what is the radius of the loop? Round your answer to the nearest whole number.
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centripetal acceleration = v^2/r to get velocity: the distance around the loop is 2pi*r. divide this by t (45 seconds) to get the velocity. then plug the velocity and acceleration into the formula, and solve for r. round to the nearest whole # as indicated.
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