A ball having a mass of 0.20 kilograms is placed at a height of 3.25 meters. If it is dropped from this height, what will be the kinetic energy of the ball when it reaches 1.5 meters above the ground? A. 1.2 joules B. 2.2 joules C. 3.4 joules D. 3.6 joules E. 4.3 joules
any kinetic energy the ball gains will come out of the original potential energy so the change in KE = mg * (the difference in heights)
I'm not sure how to do that could you explain?
the difference in heights is just 3.25m - 1.5m then multiply by mg
XD I don't think I did that right. are you saying multiply 1.75 (which is the answer to 3.25-1.5) by 0.20? That gives me 0.35
you forgot the g in mgh simply multiply your previous result by 9.8
1.75*9.8? Where did you get 9.8? that would equal 17.15 Also thank you math n stuff rly not my strong suit
g = the gravitational constant = 9.8 1.75 m * 9.8 * 0.2kg = ?
ohh 1.75 is m 9.8 is g and 0.2 is h. so 3.43 or c would be the kinetic energy of the ball when it reaches 1.5 meters above ground. Thank you!
1.75m is the height (h) and 0.2kg is the mass (m) but otherwise, yes
why do you put m after 1.75 if its the height?
m stands for meters
and mass? geez who comes up with this stuff XD
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