Question

A football quarterback has 2 more chances to throw a touchdown before his team is forced to punt the ball. He misses the receiver on the first throw 30% of the time. When his first throw is incomplete, he misses the receiver on the second throw 10% of the time. What is the probability of not throwing the ball to a receiver on either throw? (10 points)

Answer 1

So I will break the question down, It is second down. The probability is 30% 10% = .3 .1 = 0.03 = 3%

Answer 2

I think that is correct, 3% on third down.

Answer 3

are you sure its correct @foolghost14 @Imagine ?

Answer 4

I am correct, you don't add the probilitys.

Answer 5

#can't spell

Answer 6

good luck on the quiz or something

Answer 7

It is 3%

Answer 8

that is the correct answer.

Answer 9

@Imagine @foolghost14 thank you for the help guys!

Answer 10

30% 10% = .3 .1 = 0.03 = 3%

Answer 11

I ily math (3% is correct ppl)

Answer 12

can you break it down more for me?

Answer 13

Thank you @Hoodmemes :)

Answer 14

30%/10%=3%

Answer 15

Or 30/10=3

Answer 16

Whatever way you want to look at it.

Answer 17

Thanks @hiya for the medal!

Answer 18

@Imagine no problem! thank you for helping me

Answer 19

@Hoodmemes @Imagine can you guys help me with that?

Answer 20

\(\color{#0cbb34}{\text{Originally Posted by}}\) @hiya
@Imagine no problem! thank you for helping me
\(\color{#0cbb34}{\text{End of Quote}}\)
Anytime, I came to help people on here!

Answer 21

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Imagine
So I will break the question down, It is second down. The probability is 30% 10% = .3 .1 = 0.03 = 3%
\(\color{#0cbb34}{\text{End of Quote}}\)
As was said here is a correct equation etc

But how she or he got .3 and .1 was by dividing

\[30 \div 100= 0.3 =.3\]

and

\[10\div 100= 0.1=.1\]

so the last equation would have been \[.3 \times .1= 0.3\]

= 3%

Answer 22

@Hoodmemes Thank you so much for the math back-up!

Answer 23

No Problem, if you can, Please close the question :).