Question

can someone help me plezz

Answer 1

ok

Answer 2

sure

Answer 3

umm

Answer 4

First step: Simplifying
\[x+2x+40+3x−5=15,002\] Combine like terms:\[(x+2x+3x)+(40+−5)=15,002\]\[6x+35=15,002\] Second: Subtract 35 from both sides:\[6x+35−35=15,002−35\]\[6x=14,967\]Finals step: Divide both sides by 6: \[\frac{ 6x }{ 6 }=\frac{ 14,967}{ 6 }\]\[x=\frac{ 4,989 }{ 2 }\]
Leaving you with a final answer of:\[x=\frac{ 4,989 }{ 2 }\]

Answer 5

thanks u so much

Answer 6

not is correct

@umm ATTENTION please

Answer 7

Would you like to take over, @jhonyy9?

Answer 8

check it please inside second parentheses not is -5 there is -50

Answer 9

Ah, thank you. Didn't notice that.

Answer 10

and now this mean that all your work not is correct

Answer 11

oh realy

Answer 12

its ok i got it

Answer 13

\[x+2x+40+3x−50=15,002\]Simplify both sides of the equation\[x+2x+40+3x+−50=15,002\]Combine like terms\[(x+2x+3x)+(40+−50)=15,002\]\[6x+−10=15,002\]\[6x−10=15,002\]Add 10 to both sides\[6x−10+10=15,002+10\]\[6x=15,012\]Divide both sides by 6\[\frac{ 6x }{ 6 }=\frac{ 15,012 }{ 6 }\]\[x=2,502\]Final answer: \[x=2,502\]

Answer 14

\(\color{#0cbb34}{\text{Originally Posted by}}\) @umm
\[x+2x+40+3x−50=15,002\]Simplify both sides of the equation\[x+2x+40+3x+−50=15,002\]Combine like terms\[(x+2x+3x)+(40+−50)=15,002\]\[6x+−10=15,002\]\[6x−10=15,002\]Add 10 to both sides\[6x−10+10=15,002+10\]\[6x=15,012\]Divide both sides by 6\[\frac{ 6x }{ 6 }=\frac{ 15,012 }{ 6 }\]\[x=2,502\]Final answer: \[x=2,502\]
\(\color{#0cbb34}{\text{End of Quote}}\)
is that right

Answer 15

I believe so, now that I fixed my correction. @jhonyy9 -@Vocaloid, check please?

Answer 16

* @Vocaloid

Answer 17

yes right

Answer 18

Thanks again. (:

Answer 19

yw

Answer 20

anytime