Maya had $27. She spent all the money buying three burgers for x dollars each and two sandwiches for y dollars each. If Maya had bought two burgers and one sandwich, she would have been left with $11. The following system of equations models this scenario: 3x + 2y = 27 2x + y = 16 Use the system of equations to solve for x and y. (6, 5) (5, 6) (3, 2) (2, 3)
You can graph this one if you want.
But I'll let imagine finish
no it would be 17
no that would be 18
ohh i read it like the last one my bad
You can eyeball this but that's kind of cheating. \[2x + y = 16\] \[y = -2x + 16\] \[3x + 2y = 27\] \[3x + 2(-2x + 16) = 27\] \[3x - 4x + 32 = 27\] \[-x + 32 = 27\] \[-x = -5 \rightarrow x = 5\] Then just input x = 5 into either equation to solve for y
yes it would be 16
3x+2y=27 2x+y=16 now multiply by -2 -2(2x+y)=-2*16 which is 4x-2y=-32 after we can add the equations together 3x+2y=27 -4x-2y=-32 3x-4x=27-32 -x=-5 x=5 now we substitute the x 2(5)+y=16 10+y=16 y=6 therefore the solution set is (5,6)
Yup plug the y into the y of the other equation.
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