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Mathematics 31 Online
EmilyGrace1:

I need help

EmilyGrace1:

mxddi3:

2(m-4) + 1 you need to distribute the 2 into the parentheses. so 2(m) and 2(-4) then you need to take that anwer and add 1 to it. so if you have 2(m)+ 2(-4) + 1 you get what?

EmilyGrace1:

Im so confused

mxddi3:

with which part ?

6ix0weGhost:

Emily u first solve inside the parenthesis

mxddi3:

no, you must distribute into the parentheses, bc you can not do m-4

EmilyGrace1:

so I do m-4

6ix0weGhost:

Oh yeah thats the first step sorry ur right Mxddi

mxddi3:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @EmilyGrace1 so I do m-4 \(\color{#0cbb34}{\text{End of Quote}}\) no you have to multiply m-4 x 2

mxddi3:

what's 2*m and 2* (-4)

EmilyGrace1:

ok so would it be 8

mxddi3:

well 2(-4) is NEGATIVE 8, yes. but what is -8+1

EmilyGrace1:

-9

mxddi3:

no, try this, what is 1-8

EmilyGrace1:

-7

6ix0weGhost:

Yes

mxddi3:

yes. and now, again, what is 2(m) ?

EmilyGrace1:

what do I do with negative 7

mxddi3:

i'm gonna get there. you need to answer what 2(m) is first

EmilyGrace1:

Im sry im really don't get math

6ix0weGhost:

Its good I wasnt rlly good at math and I'm not really but I trry and do my best with High School Math

EmilyGrace1:

is it -2

mxddi3:

since the 2 doesn't have a negative sign, it's just positive 2, but you need to attach the variable to it. all you need to do is put the number in front of the variable.....

EmilyGrace1:

2m

mxddi3:

yes. now you remember the -7? all you do is put it after your 2m. since there is no variable on the -7 it is called you Constant. The constant goes after the term(s) with variables.

6ix0weGhost:

Now put 2m and -7 together and you get what

EmilyGrace1:

2m - -7

6ix0weGhost:

remove 1 of the -

mxddi3:

you just need one minus sign, it is with the 7.

6ix0weGhost:

since -7 is already a negative you dont need to add another - since it goes behind the 2m so the answer will be what?

EmilyGrace1:

oh ok

EmilyGrace1:

thank you both

6ix0weGhost:

Your welcome anytime but really @mxddi3 rlly deserves all the credit

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