Question

h(x) = x2 + 1 k(x) = x – 2

(h + k)(2) =

Answer 1

Ok so, \[ h(x) = x²+1 \ and\ k(x) = x-2\]
\[h(x)+k(x) = (x²+1)+(x-2)\]
\[h(x)+k(x) = x²+x-1\]
\[To\ get (h+k)(2), we\ will\ substitute x=2 into\ the\ resulting\ function\ to\ give\]
\[(h+k)(2) = 2²+2-1\]
\[(h+k)(2) = 6-1\]
\[(h+k)(2) =?\]

Answer 2

(h+k) =5
(h-k) (3)=9
3h(2) +2k(3)=17

Answer 3

@supie is right so after that then what do you do

Answer 4

oki then?

Answer 5

@xxDeppressionxx u can not give a dirrect awnser u have to let him/her figure it out

Answer 6

i didnt

Answer 7

i explained it

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @xxDeppressionxx
i explained it
\(\color{#0cbb34}{\text{End of Quote}}\)
Yeah he explained it.

Answer 9

would it be 5
and I am a him

Answer 10

ok woops my bad

Answer 11

its ok

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @JosephGunnels
would it be 5
and I am a him
\(\color{#0cbb34}{\text{End of Quote}}\)
Yeah good job.

Answer 13

good one supie, nice explanation of the work and step-by-step process

Answer 14

ur good but next time dont forget that when someone explains the answer they got its not giving a direct answer

Answer 15

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MrMudd183
good one supie, nice explanation of the work and step-by-step process
\(\color{#0cbb34}{\text{End of Quote}}\)
Thanks Mudd!

Answer 16

You're welcome :)

Answer 17

thank u i got another question to post hope yall can help