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JCapone21:

What is the mass (in grams) of 5.00 L of propane vapor (C₃H₈) at STP?

AlphaDog:

ok

AlphaDog:

so G imma be honest im only in 8th grade G

AlphaDog:

so give me a mnute

AlphaDog:

min

supie:

idk the answer so I copied from Voca \[PV = nRT\] where P = pressure, V = volume, n = moles, R is the gas constant, and T is temperature you are given STP, which implies \[P = 1\ atm\]\[T = 273K\] you are also given V = 5.00L from the problem since we are using units of atm, moles, L, K then R = 0.082057 so you can plug everything in and solve for n. to go from moles to grams, simply multiply by the molar mass of propane. This is not my work, it's Vocaloid's, I directly pulled it from: https://questioncove.com/updates/5ea31adf6f31431d9adf0c00 You can also check: https://questioncove.com/updates/5de6ff3285c62b3a881b3000

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